Writing a syntax-highlighted quine in Go

I wrote a code in Go. It's fixed-width, nicely commented and when run, outputs it's own source code:

package main;import("fmt";"strings";"regexp");func main(){ x:=(
`/* ---------------------------------------------------------`+
`-*/No:=""; P:=func(x interface{}) {o += fmt.Sprint(x)};P(Qpa`+
`ckageQ+N  Q main;import("fmt";"strings";"regexp");func main(`+
`){ x:=(Q)N  for i,ch:=range x {; if i%60==0 { P("\nQ") }; P(`+
`string(ch))N if i==len(x)-1 {P("Q)")}else if i%60==59 {P("Q+`+
`")} }; P("\n")Na:=strings.Replace(x,string(78),string(10),-1`+
`) /* newline \n */Nb:=strings.Replace(a,string(84),string(9)`+
`,-1)  /* tab     \t */Nc:=strings.Replace(b,string(81),strin`+
`g(96),-1) /* quote   \Q */NP(c); r:=regexp.MustCompile(Q(\x6`+
`b)Q); Replace :=r.ReplaceAllStringFuncNfmt.Print (Replace (o`+
`, func (x string) string {  switch x[0]  {Ncase 0x22: return`+
` "\x1b[36m"+x+"\x1b[0m"; /* "double-quoted" */Ncase 0x60: re`+
`turn "\x1b[36m"+x+"\x1b[0m"; /*  Qback-quotedQ  */Ncase 0x2f`+
`: return "\x1b[90m"+x+"\x1b[0m"; /* general comment */Ndefau`+
`lt: return "\x1b[0;1m"+x+"\x1b[0m"} })); /* keyword    */}N`)
/* ----------------------------------------------------------*/
o:=""; P:=func(x interface{}) {o += fmt.Sprint(x)};P(`package`+
  ` main;import("fmt";"strings";"regexp");func main(){ x:=(`)
  for i,ch:=range x {; if i%60==0 { P("\n`") }; P(string(ch))
 if i==len(x)-1 {P("`)")}else if i%60==59 {P("`+")} }; P("\n")
a:=strings.Replace(x,string(78),string(10),-1) /* newline \n */
b:=strings.Replace(a,string(84),string(9),-1)  /* tab     \t */
c:=strings.Replace(b,string(81),string(96),-1) /* quote   \` */
P(c); r:=regexp.MustCompile(`(\x60.*?\x60|\x22[^\n"]*\x22|/\*`+
`tch|case|return|default\b)`); Replace :=r.ReplaceAllStringFunc
fmt.Print (Replace (o, func (x string) string {  switch x[0]  {
case 0x22: return "\x1b[36m"+x+"\x1b[0m"; /* "double-quoted" */
case 0x60: return "\x1b[36m"+x+"\x1b[0m"; /*  `back-quoted`  */
case 0x2f: return "\x1b[90m"+x+"\x1b[0m"; /* general comment */
default: return "\x1b[0;1m"+x+"\x1b[0m"} })); /* keyword    */}

Right, forgot to mention - the output is syntax highlighted. Here's how it actually looks like:



It's quite simple. First you write a quine. Then you add syntax highlighting feature to it.

OK, a bit more verbose explanation:

  1. Write a quine of the form:
p1: initial boilerplate: package name, imports etc.
p2: declare a variable `x` that contains the code after itself
p3: print statement that outputs the initial boilerplate
p4: code that outputs `x`'s value representation
p5: print statement that outputs the value of `x`

The tricky part is updating the value of x in p2. Luckily, it can be automated by an external script that reads the code starting from p3 (/* --- in my case) and outputs the necessary value. The script's output is copy-pasted back into the quine once p3, p4 & p5 is polished.

I also encode certain characters that require character escaping, which will be decoded before p5. This way I don't have to deal with them in p4.

  1. Update the quine to store it's own value in a certain variable.

In the code above, it's o. This way the quine becomes "self-aware", knowing what it's source will look like prior to printing.

  1. Add ANSI escape sequences between certain terms.

I like to keep things simple, so my colorscheme only highlights keywords with bold, strings with cyan and comments with low-contrast colour.

For that, I used a hand-crafted regexp that matches certain code parts. Here's the breakdown:

\x60.*?\x60                        <- `back-quoted strings`
\x22[^\n"]*\x22                    <- "double-quoted string"
/\*.*?\*/                          <- /* general comments */
\bpackage|import|func|and|etc\b    <- reserved keywords

The matches are then wrapped in ANSI codes:

"\x1b[36m"  + x + "\x1b[0m" // cyan
"\x1b[90m"  + x + "\x1b[0m" // dark grey
"\x1b[0;1m" + x + "\x1b[0m" // bold
September 28, 2020 ยท code